Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.2 - Calculus with Parametric Curves - 10.2 Exercises - Page 655: 2

Answer

$$\frac{dy}{dx}=\frac{1+\cos t}{(t+1)e^t}$$

Work Step by Step

The formula of the derivative of a parametric equation is; $$\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}$$ Finding the derivative of both parameters with respect to $t$, we get: $$\frac{dy}{dt}=1+\cos t\\\frac{dx}{dt}=e^t+te^t=(1+t)e^t$$ Taking the ratio of the two derivatives to find $dy/dx$, we get: $$\frac{dy}{dx}=\frac{1+\cos t}{(1+t)e^t}$$
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