Answer
$$\dfrac{2}{3}$$
Work Step by Step
$$Volume=\int_{0}^{2} \int_{0}^{y}
\int_0^{(2-y/2)} dz \space dx \space dy =\int_{0}^{2} \int_{0}^{y} (1-\dfrac{y}{2}) \ dx \ dy =\int_0^2 (y-\dfrac{y^2}{2}) \ dy = \dfrac{2}{3}$$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 15 - Multiple Integrals - Review - Exercises - Page 1103: 37
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