Answer
$$\frac{\pi}{2}\left(e^{2}-1\right) $$
Work Step by Step
The volume of revolution about the $x-$ axis is given by
\begin{aligned}
V&=\pi \int_{a}^{b}f^2(x) d x \\
&=\pi \int_{0}^{1} e^{2 x} d x \\
&=\left.\pi \frac{e^{2 x}}{2}\right|_{0} ^{1} \\
&=\frac{\pi}{2}\left(e^{2}-1\right)
\end{aligned}