Answer
$\frac{e^{2}}{2} -e +\frac{1}{2}.$
Work Step by Step
The area between the two curves can be calculated as follows:
\begin{align*}
Area\ &=\int_0^1e^{2x}-e^xdx \\
&=(\frac{1}{2} e^{2x}-e^x)_0^1\\
&=\frac{e^{2}}{2} -e -(\frac{1}{2}-1)\\
&=\frac{e^{2}}{2} -e +\frac{1}{2}.
\end{align*}