Answer
$\frac{1}{4}e^{4x} +c $
Work Step by Step
Recall that $(e^x)'=e^x$
We have
$$
\int\left(e^{4x}\right) d x=\frac{1}{4}\int 4e^{4x} d x =\frac{1}{4}e^{4x} +c
$$
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