Answer
$$ e^{2} +1.$$
Work Step by Step
First, we find the intersections between the two curves by putting
$$ e^2=e^x\Longrightarrow x=2.$$
Now, the area is given by
\begin{align*}
Area\ &=\int_0^2e^{2}-e^{x}dx \\
&=( xe^{2}-e^{x})_0^2\\
&=2e^{2} -e^{2} -(0-1)\\
&=e^{2} +1.
\end{align*}