Answer
$ \frac{1}{4}(e^{9}-e^5 )$
Work Step by Step
We have $$ \int_2^3 e^{4t-3} dt= \frac{1}{4}\int_0^34e^{4t-3} dt = \frac{1}{4}\left[e^{4t-3}\right]_2^3= \frac{1}{4}(e^{9}-e^5 ) . $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.1 Derivative of f(x)=bx and the Number e - Exercises - Page 328: 74
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
