Answer
$-2(e^{-3}-e^{-1})$
Work Step by Step
We have
$$
\int_2^5\left(e^{-\frac{x}{2}}\right) d x=-2\int_2^5\left(-\frac{1}{2}e^{-\frac{x}{2}}\right) d x =-2\left[e^{-\frac{x}{2}}\right]_2^6= -2(e^{-3}-e^{-1})
.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.1 Derivative of f(x)=bx and the Number e - Exercises - Page 328: 72
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