Answer
$-\frac{1}{3}(e^{-3}-1)$
Work Step by Step
We have $$ \int_0^1\left(e^{-3x}\right) d x=\frac{1}{-3}\int_0^1 -3e^{-3x} d x =\frac{-1}{3}\left[e^{-3x}\right]_0^1= -\frac{1}{3}(e^{-3}-1) . $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.1 Derivative of f(x)=bx and the Number e - Exercises - Page 328: 71
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