Answer
$$
\int(x+25)^{-2} d x=-\frac{1}{x+25}+c.
$$
Work Step by Step
Since $ u=x+25 $, then $ du=dx $ and hence, $$
\int(x+25)^{-2} d x=\int u^{-2} d u=- u^{-1}+c\\
=-(x+25)^{-1}+c=-\frac{1}{x+25}+c.
$$
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