Answer
$\frac{1}{4}(x-7)^{4}+C$
Work Step by Step
Substituting u=x-7 so that du=dx, we get
$\int (x-7)^{3}dx= \int u^{3}du= \frac{u^{4}}{4}+C$
Undoing substitution, we have
$\int (x-7)^{3} dx= \frac{1}{4}(x-7)^{4}+C$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.7 Substitution Method - Exercises - Page 275: 7
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