Answer
$y=3t^3+t^2-2$
Work Step by Step
$\frac{dy}{dt}=2t+9t^2;$ $y(1) = 2$
$dy=(2t+9t^2)dt$
$\int dy=\int(2t+9t^2)dt$
$y=t^2+3t^3+C$
$2=1^2+3(1^3)+C$
$C=-2$
$y=3t^3+t^2-2$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 49
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
