Answer
$$\frac{1}{12} \sec(12t)+c$$
Work Step by Step
Since $(\sec(12t ))'=12 \sec(12t )\tan(12t )$, we have
$$\int \sec(12t )\tan(12t ) dt=\frac{1}{12}\int 12\sec(12t )\tan(12t ) dt \\
=\frac{1}{12} \sec(12t)+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 35
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