Answer
$\int18x^2= 6x^3 + C$
Work Step by Step
Anti-differentiation: $\int18x^2= 18\int x^2= 18\times\frac{1}{1+2} x^3 + C= 18\times\frac{1}{3}x^3 + C =6x^3 +C $
Checking with differentiation:
$(6x^3+ C)' = 6\times3 x^2 = 18x^2 $
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 1
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