Answer
$y=\frac{x^4}{4}+4$
Work Step by Step
$\frac{dy}{dx}=x^3;$ $y(0)=4$
$dy=x^3dx$
$\int dy=\int x^3dx$
$y=\frac{x^4}{4}+C$
Substitute in initial condition
$4=0+C$
$C=4$
$y=\frac{x^4}{4}+4$
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