Answer
$\int\frac{12-z}{\sqrt z}dz =24z^\frac{1}{2}-\frac{2}{3}z^\frac{3}{2} +C $
Work Step by Step
$\int\frac{12-z}{\sqrt z}dz = \int12z^{-\frac{1}{2}} - z^{\frac{1}{2}} dz = 12\times\frac{1}{\frac{1}{2}}z^\frac{1}{2}- \frac{1}{\frac{3}{2}}z^\frac{3}{2} +C = 24z^\frac{1}{2}-\frac{2}{3}z^\frac{3}{2} +C $
