Answer
$$12\sec{x}+C$$
Work Step by Step
$\int 12\sec{x}\tan{x} dx$
Pulling 12 out of the integral:
$12\int\sec{x}\tan{x} dx$
Given $$\int\sec{x}\tan{x} dx=\sec{x}+C$$
$12\int\sec{x}\tan{x} dx$
$=12\sec{x}+C$
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