Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 27

Answer

$$12\sec{x}+C$$

Work Step by Step

$\int 12\sec{x}\tan{x} dx$ Pulling 12 out of the integral: $12\int\sec{x}\tan{x} dx$ Given $$\int\sec{x}\tan{x} dx=\sec{x}+C$$ $12\int\sec{x}\tan{x} dx$ $=12\sec{x}+C$
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