Answer
$\int\frac{dx}{x^{\frac{4}{3}}} = -3x^{-\frac{1}{3}}+C$
Work Step by Step
$\int\frac{dx}{x^{\frac{4}{3}}} = \int x^{-\frac{4}{3}} dx= \frac{1}{-\frac{1}{3}}x^\frac{-1}{3}+C = -3x^{-\frac{1}{3}}+C$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 20
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