Chapter 2 - Limits - 2.7 Limits at Infinity - Exercises - Page 83: 40

$$16$$

We find the limit as follows: \begin{align*} \lim _{t \rightarrow-\infty} 2\left(\frac{8 t}{t+1}+10^{t+1}\right)&=\lim _{t \rightarrow-\infty} 2\left(\frac{8 t}{t+1} \right)+\lim _{t \rightarrow-\infty} 2\left( 10^{t+1}\right)\\ &= 2(8)+0\\ &=16 \end{align*}