Answer
$\frac{4}{5}$
Work Step by Step
We have
$$
\lim _{t \rightarrow-\infty} \frac{4+5^{2 t}}{5-5^{3 t}}= \frac{4+5^{-\infty}}{5-5^{-\infty}}=\frac{4+0}{5-0}=\frac{4}{5}
$$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.7 Limits at Infinity - Exercises - Page 83: 30
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