Answer
$\infty $
Work Step by Step
We have
\begin{align*} \lim _{x \rightarrow \infty}\frac{\sqrt{x^3+20x}}{10x-2} &=\lim _{x \rightarrow \infty}\frac{x\sqrt{x+\frac{20}{x^2}}}{x(10-\frac{2}{x})}\\ &=\frac{\sqrt{\infty+0}}{10-0} \\
&=\infty
\end{align*}