Answer
The path of the curve will be at some $t$ higher and at some $t$ lower than the generating circle.
Work Step by Step
From Exercise 77 we obtain the parametric equation of the cycloid:
$c(t)=(R{\ }t-h \sin t,R-h \cos t)$.
In the case $h>R$, the path of the curve will be at some $t$ higher and at some $t$ lower than the generating circle. Since the lowest point of the circle is at $y=0$, the curve will at some point goes below the $x$-axis. This is illustrated in the figure attached.
