Answer
$10arcsin(e^t)+C$
Work Step by Step
$\frac {dr}{dt}=\frac {10e^t}{\sqrt{1-e^{2t}}}$
$r=\int \frac {10e^t}{\sqrt{1-(e^t)^2}}$
$10arcsin(e^t)+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 513: 53
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