Answer
$f'(x)=x(2\tan(x)+x\sec^2(x))$.
Work Step by Step
Product Rule $f'(x)=((u(x)(v(x))’=u’(x)v(x)+u(x)v’(x))$
$u(x)=x^2 ;u’(x)=2x $
$v(x)=\tan(x) ;v’(x)=\sec^2(x)$
$f'(x)=(2x)(\tan(x))+(\sec^2(x))(x^2)$
$=x(2\tan(x)+x\sec^2(x))$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.3 Exercises - Page 125: 51
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