Answer
$f'(t)=t(2\sin(t)+t\cos(t))$
Work Step by Step
Product Rule $f'(t)=((u(t)(v(t))’=u’(t)v(t)+u(t)v’(t)$
$u(t)=t^2 ;u’(t)=2t $
$v(t)=\sin(t) ;v’(t)=\cos(t) $
$f'(t)=(2t)(\sin(t))+(\cos(t))(t^2)=t(2\sin(t)+t\cos(t))$
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