Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises - Page 125: 31

Answer

$h'(s)=6s^2(s^3-2)$

Work Step by Step

$h(s)=(s^3-2)^2=s^6-4s^3+4$ $h'(s)=6s^5-12s^2=6s^2(s^3-2)$
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