Answer
$$h'(x)=2x\cosh{(x^2)} $$
Work Step by Step
$h'(x)=\frac{d}{dx}\sinh {(x^2)}$
Using the chain rule:
$h'(x)=\frac{d\sinh {(x^2)}}{dx^2}
\times \frac{dx^2}{dx}$
$=\cosh {(x^2)} \times 2x$
$=2x\cosh{(x^2)} $
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises - Page 267: 37
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
