Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 3 - Review - Exercises - Page 271: 85

Answer

$h'(x) = (4~cos~4x)\cdot f'(g(sin~4x))\cdot g'(sin~4x)$

Work Step by Step

$h(x) = f(g(sin~4x))$ $h'(x) = f'(g(sin~4x))\cdot \frac{d}{dx}(g(sin~4x))$ $h'(x) = f'(g(sin~4x))\cdot g'(sin~4x)\frac{d}{dx}(sin~4x)$ $h'(x) = (4~cos~4x)\cdot f'(g(sin~4x))\cdot g'(sin~4x)$
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