Answer
$$f'(x)=2xg(x)+x^2g'(x)$$
Work Step by Step
$f'(x)=\frac{dx^2g(x)}{dx}$
Using the product rule:
$f'(x)=2xg(x)+x^2g'(x)$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Review - Exercises - Page 271: 75
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