Answer
$f'(x) = g'(e^x)\cdot e^x$
Work Step by Step
Let $h(x) = e^x$
$h'(x) = e^x$
We can find $f'$:
$f(x) = g(e^x)$
$f(x) = g(h(x))$
$f'(x) = g'(h(x))~\cdot h'(x)$
$f'(x) = g'(e^x)\cdot e^x$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Review - Exercises - Page 271: 79
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