Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 3 - Review - Exercises - Page 271: 78

Answer

$$f'(x)=g'(g(x))\times g'(x)$$

Work Step by Step

$f'(x)=\frac{d}{dx}g(g(x))$ Using the chain rule: $f'(x)=\frac{dg(g(x))}{dg(x)}\times\frac{dg(x)}{dx}$ $=g'(g(x))\times g'(x)$
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