Answer
a) $x=e^e$
b) $x=\frac{\ln C}{a-b}$
Work Step by Step
a) $\ln (\ln x)=1$
$e^{\ln (\ln x)}=e^1$
$\ln x=e$
$x=e^e$
b) $e^{ax}=Ce^{bx}$
$\frac{e^{ax}}{e^{bx}}=C$
$e^{(a-b)x}=C$
$(a-b)x=\ln C$
$x=\frac{\ln C}{a-b}$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 65: 54
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