Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 65: 39

Answer

$\ln250$

Work Step by Step

$\ln10+2\ln5=\ln10+\ln5^2=\ln(10\times5^2)=\ln250$
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