Answer
$\ln{\frac{bc^2}{d^3}}$
Work Step by Step
$\ln b+2\ln c-3\ln d=\ln b+\ln c^2-\ln d^3=\ln{\frac{bc^2}{d^3}}$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 65: 40
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