Answer
a)$\log_2{32}=5$
b)$\log_8{2}=\frac{1}{3}$
Work Step by Step
a)$\log_2{32}=\log_2{2^5}=5\log_2{2}=5$
b)$\log_8{2}=\log_8{8^\frac{1}{3}}=\frac{1}{3}\log_8{8}=\frac{1}{3}$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 65: 35
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