Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 65: 36

Answer

a) $\log_5\frac{1}{125}=-3$ b) $\ln(\frac{1}{e^2})=-2$

Work Step by Step

a) $\log_5\frac{1}{125}=\log_5{5^{-3}}=-3\log_5{5}=-3$ b) $\ln(\frac{1}{e^2})=\ln e^{-2}=-2\ln e=-2$
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