Answer
a) $e^{-\ln2}=\frac{1}{2}$
b) $e^{\ln(\ln e^3)}=3$
Work Step by Step
a) $e^{-\ln2}=e^{\ln2^{-1}}=e^{ln\frac{1}{2}}=\frac{1}{2}$
b) $e^{\ln(\ln e^3)}=\ln e^3=3\ln e=3$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 65: 38
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