Answer
$d = \sqrt\frac{kP_{1}P_{2}}{C}$
Work Step by Step
$C = \frac{kP_{1}P_{2}}{d^2}$. Solve for $d$.
$Cd^2 = kP_{1}P_{2}$
$d^2 = \frac{kP_{1}P_{2}}{C}$
$d = \sqrt\frac{kP_{1}P_{2}}{C}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 593: 68
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