Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 593: 38

{$-1-\sqrt {6},-1+\sqrt {6}$}

Given: $x^2+2x=5$ We need to add $1^2$ to complete the square. Thus, $x^2+2x+1^2=5+1$ or, $x^2+(2)(1)(x)+1^2=6$ or, $(x+1)^2=6$ or, $(x+1)=\pm \sqrt {6}$ or, $x=-1- \sqrt {6},-1+\sqrt {6}$ Hence, solution set is $x=${$-1-\sqrt {6},-1+\sqrt {6}$}