Answer
{$-7,1$}
Work Step by Step
Given: $x^2+6x=7$
We need to add $3^2$ to complete the square.
Thus,
$x^2+6x+3^2=7+9$
or, $x^2+(2)(1)(3x)+3^2=16$
or, $(x+3)^2=4^2$
or, $(x+3)=\pm 4$
or, $x=1,-7$
Hence, solution set is $x=${$-7,1$}
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 593: 36
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