Answer
{$-8,4$}
Work Step by Step
Given: $x^2+4x=32$
We need to add $2^2=4$ to complete the square.
Thus,
$x^2+4x+2^2=32+4$
or, $x^2+(2)(1)(2x)+2^2=36$
or, $(x+2)^2=6^2$
or, $(x+2)=\pm 6$
or, $x=4,-8$
Hence, solution set is $x=${$-8,4$}