Answer
$3x$
Work Step by Step
RECALL:
The quotient rule:
$\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}=\sqrt[n]{\dfrac{a}{b}}$
where
$\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne0$
Use the rule above to obtain:
$\require{cancel}=\sqrt{\dfrac{54x^3}{6x}}
\\=\sqrt{\dfrac{\cancel{54}9\cancel{x^3}x^2}{\cancel{6x}}}
\\=\sqrt{9x^2}
\\=\sqrt{(3x)^2}$
Simplify to obtain:
$=3x$
