Answer
$2$
Work Step by Step
RECALL:
The quotient rule:
$\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}=\sqrt[n]{\dfrac{a}{b}}$
where
$\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne0$
Use the rule above to obtain:
$=\sqrt[3]{\dfrac{48}{6}}
\\=\sqrt[3]{8}
\\=\sqrt[3]{2^3}$
Simplify to obtain:
$=2$
