Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 427: 56

Answer

$\frac{19x+10y}{(x+y)(x-y)}$

Work Step by Step

$\frac{9x}{x^2-y^2}-\frac{10}{y-x}=\frac{9x}{(x+y)(x-y)}+\frac{10}{x-y}=\frac{9x}{(x+y)(x-y)}+\frac{10(x+y)}{(x-y)(x+y)}=\frac{9x+10x+10y}{(x+y)(x-y)}=\frac{19x+10y}{(x+y)(x-y)}$
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