Answer
$0$
Work Step by Step
$\frac{y-3}{y^2-25}+\frac{y-3}{25-y^2}=\frac{y-3}{y^2-25}-\frac{y-3}{-(25-y^2)}=\frac{y-3}{y^2-25}-\frac{y-3}{y^2-25}=0$
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