Answer
$(x-4)^2(x+4)$
Work Step by Step
$x^2-8x+16=(x-4)^2$, $x^2-16=(x+4)(x-4)$, so the GCF is $x-4$ and the terms that are "not common" are $x-4$ and $x+4$ so LCD$=(x-4)(x-4)(x+4)=(x-4)^2(x+4)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 427: 23
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