Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Cumulative Review Exercises - Page 251: 18

Answer

$23$

Work Step by Step

We know that for a matrix \[ \left[\begin{array}{rrr} a & b & c \\ d &e & f \\ g &h & i \\ \end{array} \right] \] the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$ Hence here $D=0(0\cdot5-(-4)\cdot0)-1((-7)\cdot5-(-4)\cdot3)+(-2)((-7)\cdot0-0\cdot3)=0(0)-1(-23)+(-2)(0)=23$
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