Answer
The graph is shown below.
Work Step by Step
The given equation of the line is
$\Rightarrow f(x)=−\frac{2}{3}x+2$
let $f(x)=y$.
$\Rightarrow y=−\frac{2}{3}x+2$
Plug $y=0$ for the $x−$intercept.
$\Rightarrow 0=−\frac{2}{3}x+2$
Add $\frac{2}{3}x$ to both sides.
$\Rightarrow 0+\frac{2}{3}x=−\frac{2}{3}x+2+\frac{2}{3}x$
Simplify.
$\Rightarrow \frac{2}{3}x=2$
Isolate $x$.
$\Rightarrow x=3$
The $x−$intercept is $3$, so the line passes through $(3,0)$.
Plug $x=0$ for the $y−$intercept.
$\Rightarrow y=−\frac{2}{3}(0)+2$
Simplify.
$\Rightarrow y=2$
The $y−$intercept is $2$, so the line passes through $(0,2)$.
Checkpoint plug $x=6$.
$\Rightarrow y=−\frac{2}{3}(6)+2$
Simplify.
$\Rightarrow y=−4+2$
$\Rightarrow y=−2$
The checkpoint is $(6,-2)$.
Draw a straight line through these three points.
