Answer
$(f-g)(1)=-3$
Work Step by Step
Since, we have $f(x)=2x^2-5x+2$ and $g(x)=x^2-2x+3$ Now,
$f(x)-g(x)$ or $(f-g)x=x^2-3x-1$
Now, when $x=1$, we get $(f-g)(1)=1^2-3-1=1-4=-3$
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