Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Cumulative Review Exercises - Page 251: 1

Answer

$1$

Work Step by Step

$\frac{6(8-10)^3+(-2)}{(-5)^2(-2)}\\=\frac{6(-2)^3+(-2)}{25(-2)}\\=\frac{6(-8)+(-2)}{-50}\\=\frac{-48+(-2)}{-50}\\=\frac{-50}{-50}=1$
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